Gaston wrote:For liquid water, the specific heat is 4 J · kg−1· K−1.
For vaporization, the enthalpy is 2 Jkg−1
Passing 1kg of liquid water at 20 ° to steam at 100 ° therefore requires 80 * 4185 + 2264000 = 2431400 675 J = XNUMXWh
Uh good reasoning, I arrive at 722 Wh but that does not change much in the final result ... logically it would also take into account the rise in the temperature of the steam, right? But up to what temperature? That of smoke or combustion?
Gaston wrote:In total, 1% more humidity represents about 50Wh / kg less.
It's a lot less than I actually thought *, finally 1% of water, it is approximately 1% of PCI in less... but I had never done this reasoning ...
Gaston wrote:Note that in the case of moisture uptake, it is "only" 6,75 Wh because the weight of pellets burned has also increased by the quantity of water absorbed.
No understands?
* I happened to burn wood that was not dry enough and it was catastrophic ... much more than the 20% difference (but it's very subjective as a remark ...)