Woodcutter wrote:citro wrote:Bolt wrote:there was one at the invention of the year competition on M6, its blades were ordered to rotate and avoid the wind
but the guy didn't understand how a wind turbine works
horizontal axis : he said that the air passing between the 3 pale "fines" did not produce useful recoverable energy (to enhance his invention), that was the thing not to say
because big bullshit
Could you explain to us why, bolt?
Yes, bolt, could you?
If we rely on the formula giving the wind energy: E = 1 / 2.rhô.S.Vcube
with rhô = density of air
S = blade area
V = wind speed
we can see that indeed, the surface of a conventional wind turbine blade is not very large compared to the surface it sweeps during its rotation.
So
unless the formula is wrong, I do not see where is the "big bullshit" which made our tractor driver come off its hinges forumesque ...
hello lumberjack and citro (I hadn't seen citro's message: already 3 months, excuse me!
)
you could find all alone by browsing explanations here and there on the net (like I did, moreover, 1 year ago I only knew dale in the wind principle)
I will try to make you understand with my logic of poor "cincier" ("peasant" in patois):
The energy of the wind (or of the water of a watercourse) depends (to start) only on its kinetic energy: either in watt / sec:
P = 1/2 m V²
V in m / sec
m being the mass (of the fluid) / sec, this is equivalent to: its specific weight (1,25 kg / m3 for air) x its "flow" (flow = volume / sec)
note: P being a power (work per unit of time) m is therefore a "mass per unit of time"
if we only took inertia we would have:
E = 1/2 M V² with M being only a massflow (Q) which is, itself: a surface advancing in a direction at a certain speed (Q = S x V)
Q in m3 / sec
S in m²
V in m / sec
therefore, the kinetic energy of a fluid is:
P = 1/2 m V² which, broken down, is also
P = 1/2 x rhô x S x V ^ 3
rhô being the specific weight of the fluid in kg / m3
S being the concerned surface of the fluid in question
V being the speed in m / sec of the fluid in question
that's why (and it took me a while to explain it to myself
) the energy is proportional to the cube of the speed and not to the square of the speed of the fluid
it was to explain the "starting" power of the wind
and the only way to take energy from this "continuous kinetic energy" is to break it, in other words to reduce its speed.
and as the power of the wind is proportional to the cube of this speed, even decreasing it slightly is particularly worth the candle
now, exploiting it is another story: to this formula, we must add a
coefficient of performance due to air friction on the blades (or the blade)
and as the pressure drops (as in a water pipe or an air duct) are proportional to the
contact surface where friction is created, the less surface, the better
and as it suffices to lower the wind speed very little to recover a lot of energy (relationship with the cube of the speed)
it is much better to lower the speed of a large area with little propeller blade area a little than to have the same propeller area for little "slowed up wind" area
as a power is expressed by a couple x by a speed; high speed is welcome
what matters is to break the kinetic energy of the speed and mass of the wind without selling it off with non-recoverable friction of energy: it is enough to punctually take a spot from the sky where the air is well launched, capture that momentum instantly; but when the momentum of this place is broken, it is not worth much to linger there, it is better to capture its neighbor as slender as possible
they even made wind turbines to 2 see a single pale with the pain of having to add diametrically opposite a counterweight
the guy from M6 is only right for the start-up time: the surface normally swept by a 3 blades is then not precisely swept
and the inertia of the wind is only broken by the surface of the blades
but for the question it is necessary to take into account the swept surface and not the windward surface of the pale only
that said, I do not know the performance of its principle in comparison with a 3 pale wind turbine
large wind turbines have a propeller diameter of 80 m, and the tip of the blades can exceed the speed of 400 km / h I believe
so it quickly passes from one place to another to break the kinetic energy of the air
there is certainly a compromise to be found between the friction forces (whose energy is lost) generated by the surface
in touch and
air penetration speed with energy recoverable at the output of the propeller axis
imagine a wind turbine with 3 blades of which 9 would have been added to make 12 blades, it is not at all sure that the energy produced is greater, except perhaps at low speed where the wind speed is low, the forces friction is reduced and a 3 blades would break the kinetic energy of the wind at too low frequency (the wind would have, between each pale, much more than the time necessary to recover its cruising speed)
he said that the air passing between the 3 pale "fines" did not produce useful recoverable energy
it is true that by taking the words quoted, the air passing between the fine pale does not touch anything, so can not logically advance anything, but the principle is not so simple
What do you think
bolt