I do not know agricultural measurement units at all and it always seems to me like another planet, can one really apply agricultural calculations to ridiculous dimensions compared to our vegetable gardens (which themselves are large or medium vegetable gardens .. but try to push the cipher to the end to compare with the lowenfels thresholds, chick! ...Did67 wrote:A contribution of 40 gross tons / ha every 3 years [an average dose, today very little practiced! This is the equivalent of 4 kg / m² in the kitchen garden, ie 400 kg on 100 m²] brings about 350 units of P. It is indeed, quite significant and corresponds to the needs of the 3 cultures that will succeed one another.
In addition it will make me revise my memories (which seem to me so old ) of terminal S!
First of all you have voluntarily enlarged I imagine (?) The result?
3.5 units of P / ton * 40 tons = 3.5kg * 40 = 140 kg of P contributed by ha = 140 units / ha (and not 350 ???).
But sorry I am probably confused with the agricultural measures and I am not sure at all: you say "350 units of P" = 350kg of phosphorus for a ha, is that it?
Let's assume if you take your number as a precaution: 350 kg / ha = 35 mg for 1m2 (because 1ha = 10000m2).
For the rest I do not know how many kg of land can be counted m2 (I imagine that if we do not bury too much manure, phosphorus remains in the first 10 cm .. ) but that corresponds to a few kilos I imagine..Disally 3 (but it must be more!) So we would 35mg / 3 = 12mg / kg and so we would be, counting wide, and the wet finger, at 7 times below the threshold given by Lowenfels (80mg / kg).
By the way, when you say 4 kg / m2 it's about a good shovel by m2 every 3 years is that?