Testing and calculation of actual COP with air conditioning Airton

Tests and performance tests on an air conditioning

Reversible heat pumps Inverter are "in fashion", many are installed either for the air conditioner mode or for heating mode, or 2.

What are the real price of a 1er heat pump performance (euros 549 + connection kit)?

Inverter air conditioner Airton

We tried to find out by estimating the instant COP of an Airton Inverter model.

Inverter air conditioner Airton

The outdoor battery of this air conditioning is located in a greenhouse facing due EAST. Debate on the interest of placing the air conditioning outdoor unit in a greenhouse.

Mesures

Measurement conditions

Outdoor T ° (in the greenhouse): 36 ° C / 48% RH

° Indoor: 25.2 ° C

temperature set aircon: 32 ° C (max to avoid regulations)

blowing area of ​​the air conditioning: 0.0536 m²

Prince measures

Principle: we estimate the power of the air blown by the air conditioning by measuring flow and temperatures.

Measurements made with this anemometer which gives the instantaneous speed and temperature of the air flow.

handheld anemometer

Protocol: I 4 measurement points along the fan, as perpendicular as possible to the flow, I note and T ° km / h at each point.

The temperature must stabilize so I measure 1 minute after moving the anemometer.

The averages of these 4 points are obtained and a measurement of volume flow and T ° "hot" is obtained.

I correct the volume flow with the density of the air (which varies greatly between 25 ° and 40 ° C) to obtain the mass flow of air.

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With indoor T °, ​​it is a heat balance and we get the power restored heater.

I measure the electrical power consumed by a power meter on outlet

COP is obtained by dividing the 2!

Measurements (performed 10 minutes apart starting at T = 10 min and in chronological order)

1 measure:

Pu = 1032W

T ° = inner 25.2 ° C
T ° = Hot 33.38 ° C
4.72 blower speed = m / s
Volume flow = 0.2527 m3 / s
Density at 32.5 1.155 ° C = kg / m3
(from http://fr.wikipedia.org/wiki/Masse_volumique_de_l%27air)
Mass flow = 0.2919 kg / s
Pc 1004 air = J / kg. ° C

Power output W = 2396

COP = 2.32

2 measure:

Pu = 950W

T ° = inner 25.2 ° C
T ° = Hot 36 ° C
4.35 blower speed = m / s
Volume flow = 0.2330 m3 / s
Density at 35 1.146 ° C = kg / m3

Mass flow = 0.2670 kg / s
Pc 1004 air = J / kg. ° C

Power output W = 2889

COP = 3.04

3 measure:

Pu = 650W

T ° = inner 25.2 ° C
T ° = Hot 39.4 ° C
4.19 blower speed = m / s
Volume flow = 0.2245 m3 / s
Density at 40 1.127 ° C = kg / m3
Mass flow = 0.2530 kg / s
Pc 1004 air = J / kg. ° C

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Power output W = 3593

COP = 5.53

Conclusion

The last COP measured far exceeds the expected 4, the advantage of placing the outdoor unit in a warm room is therefore confirmed. More analyzes in the link below.

More: debate on the actual COP of an Airton air conditioning system

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