The yield of a nuclear plant

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QUESTION: What is the yield of a nuclear plant?

ANSWER : the yield of a nuclear plant is of the order of 30%.

EXPLANATION: This means that 70% of the "atomic" energy from the fission of uranium 235 is "wasted" in heat in the cooling towers.

For a plant reactor 2 1,3 electric GW, this corresponds to a heat loss of about 6 GW and an atomic power 8,6 GW.

These 6 GW are "evacuated" in the cooling towers of the French power plants, there is one tower per reactor (so you can easily know the number of reactors of a power plant by counting the number of turns).

Heating requirements of a modern home are roughly (smoothed over the year) of 60 W by m2. Whether for a house m100 2, 6 kW.The "lost" thermal energy of a single plant at 2 reactors is therefore the heating of a million homes!

Assuming (which is not the case but for the image) that was recovered as energy cogeneration 14 16 to nuclear reactors would be enough to heat the whole of France without any consumption of heating or electrical or fuel oil or gas!

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1 comment on "The performance of a nuclear power plant"

  1. the number of "cooling towers" does not correspond to the number of reactors, eg the "Bugey" generating station
    has 4 reactors "REP of 900 MW"; two reactors (bugey 2 and 3) do not have cooling towers and two rep reactors of 900 mw (bugey 4 and 5) have two cooling towers per reactor; Another example: Tricastin power plant, two cooling towers for
    4 reactors, therefore, no ratio between the "number of cooling towers / number of reactor".

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