I have installed this device:
I have not chosen at random you can appreciate
First, an inverter or nothing
Inverter means that all motors are proportionally variable, regulation also (important), it allows for this model to modulate the power according to the differential between the measured T ° and the set point between 1800 mini and 5300Wmax
this will play on the COP for example by limiting the power of the indoor unit (ie selecting the low speed or night mode), which allows to oversize the exchanger ext. (Evaporator) to the needs
Prefer the refrigerant R410A which has a very low T ° of evaporation (° C -55 P. atm) and allows the operation of heating to Bouzin -15 ° C
Then, you should know that the manufacturers often use the same "box" (fairing, exchangers) for different powers, thus penalizing the most powerful model in the range of the same size.
this is the reason why I selected the first model; a comfortable difference seen (3.5 4.3KW and average speed) between the cold and warm powers displayed, which implies a good restitution of the energy consumed by the compressor
This is not the case of the model above whose powers are limited to cold: 5,1 kw, hot: 5,6 kw due to an under sizing the exchangers.
Capt_Maloche wrote:Come early results, quite amazing for a camera of this price: Split System Inverter R410A 3500W given to medium and max 5300W
Split adjusted low speed (so oversized heat exchangers)
Low speed in Eco mode, 3 + ° C outside to 21h00
Absorbed power indicated by the]PM 230 : 565W 228V 50Hz cos Phi: 0.98 2.54A (extra information)
blow surface of the indoor unit: x 0.60 0.08 m²
average speeds measured on 12 points: 5.1 m / s (hot wire anemometer KIMO)
Is a flow 880m3 / h
T ° uniform blowing 32 ° C
T ° recovery 22 ° C (installed in the upper part)
an actual power output of 880 0.34 x x (32-20) W = 2992
COP = 2292 / 565= 5.2 quite the cattle
0.34 is a contraction of the specific heat of air 20 50% ° C widely used in the business
Then the power P = (Q v / 3600) x Cp x x Ro DT is the full form.
P [W]
Qv [m3 / h]
Cp [J / kg.K]
Ro [kg / m3]
DT [K]
Typical values are: http://www.thermexcel.com/french/tables/massair.htm
Cp = 1000 [J / kg.K]
Ro = 1.25 [kg / m3] you can quibble with 1.20
This explains the formula used most commonly:
= P x Q v x 0.34 DT (where 0.34 1000 * = 1.25 / 3600)
Assume the constant Pc and Ro values.
This power formula is valid for hot and cold batteries batteries if the condensation does not occur. (If condenstation take the enthalpy difference).
And so here it is installed inside:
You can see the PM230 left of the chute
The indoor unit is placed above the door in the lobby that serves the whole house
bottom right the kitchen, left the bottom Sat stay right the downstairs bedroom (not the closet), left the office and I took the photo at the foot of the staircase leading upstairs
Capt_Maloche wrote:citro wrote:I did a quick calculation table corner ...
Compared to all or nothing reversible € 250 purchased by my brother frêre 4 years ago (COP2.5), this version less than € 600 pays for itself in less than 2 years ...
Now what would interest me would be to know your total kWh thermal generation over a year and your consumption kWh electric ...
'Cause you're not going to have a COP of 5 in freezing temperatures ...
I should monetize the thing in less than a year, providing cost me around 900L price of oil, I decided to buy it than to complete the full of my tank
I measure my years since 2 fuel oil consos
I will add grace to PM230 consos of the air conditioning and heating mode and compare and verify the return on investment
You know, for negative temperatures, in fact it is a relatively short time a yearI who come to invest in a gas condensing boiler ... I wonder if your choice is not cheaper than gas ... The kWh of gas was € 7 2008 percent but it blazed in 2009 (the price of subscription doubled).
I made my calculation, at energy cost is no concurrency, except perhaps wood (4fois cheaper than fuel oil)
It is also without concurrency on the purchase price
But gas is not too badly placed 157 0.0489 € subscription and € by kw.h
With the split inverter and an average COP of 4 say the Kw.h cost me 0.10 / 4 0.025 = € / night without Kw.h price, I have not changed my subscription EDF.
(The gas you have a subscription and more) in which amounts to around an annual consumption of 10 000KW.h to 157 / 10 000 1.57 = cent of € 0.0489 or more 0.0157 + = 0.0646 € / Kw.h which it must add the efficiency of the plant
and comparisons around € 0.08 / Kw.h for oil with an average yield
Christophe wrote: Operating 24h on how many days? When I met 1 able pm I always put a post it close with the start time and date measurements.
I charge a monthly statement
I see mostly hit Bouchou brass hung left!
This is an emergency?
Nah, it's a rustic pulls plug polished wood, which can indeed serve nutcracker and crushed fingers
Ah I saw it more "open" from what you were saying ... the inverter has an "effect" in the kitchen for example and on the 1st floor? Well, you will tell me it's extra ... obviously!
Say it is centrally placed:
1 3 stay radiator based on
Kitchen and toilet (not pictured) radiator according
Office, hall and bedroom on the ground floor closed radiators
1 bathroom upstairs radiator according
3 rooms upstairs closed radiators (thermostat set at 18 ° C in case, good temp for sleeping)
Apartment DRC closed down all radiators, unheated garage, unheated porch.
With that, I have more than 25% of radiators based [/ quote
