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1er step towards the unknown, Electric Motor Differential Analysis!

An electric coil motor can not operate fully according to the theory

Principle to know
If one opposes in repulsion,
a magnet of 10g to a magnet of 1g,
what will be the repelling force, 1OKg or 1Kg? Survey

Differential analysis!

According to the current theory
If we inject 1Kw into an 1Kw engine,
it will repel at mechanical 1Kw


But in practice,
In this case, we can not have simultaneously
1Kw on the stator and 1Kw on the rotor

the electric Kw will be divided into 2,
500W on the stator, 500W on the rotor,
to get 500w mechanical util



When the permanent magnet motor, it works perfectly,
since we oppose a power of repulsion magnets
at the same level as the electric power injected
Here in practice,
1Kw electric injector is injected on the stator, the permanent magnets of the rotor repel mechanical 1Kw,
to get 1Kw mechanical util


Conclusion
The coils of an electric motor with coils do not behave like permanent magnets.

Speaking of electric motor, did you see the engines of the new AGV train?
Obviously these are motors called "brushless" which for a volume ultimately not so large that it develops 1000hp at 4000rpm
It's enormous !
The biggest electric motor I saw in my career was 600ch and it was about the size of a car.

??

Hic wrote:1er step towards the unknown, Electric Motor Differential Analysis!

An electric coil motor can not operate fully according to the theory
.....

At the bear,

You will take courses in electrical engineering to explain your nonsense.

I have taken courses!
Should you learn the fancais?

I repeat my question!

How is it possible that an engine can generate mechanical 1Kw on the axis,
by injecting him only 1Kw electric

So as to have a mechanical 1Kw force on the axis,
It takes 2 equal magnetic fields of 1KW magneto-mechanical EACH,
isssus an electrical power of 1KW every !!!!!!!


We note that
That's what you get on a permanent magnet motor,
1kw élecrtique + 1KW in magneto-mechanical repulsion of the magnets of the rotor = 1KW mechanical on the axis.It is OK!

and therefore a total of 2Kw magneto-mechanical in repulsion for mechanical 1KW on the axis




but on a motor with coils, the electric KW can not convert to 2 1KW magneto-mechanical




unless it is "like" the multiplication by zero of the buns or the wine! MAGIC!! but that is the domain of faith


If you do not understand it is that you do not want to understand
it's closing minds !!!

See you soon

moinsdewatt wrote:

Hic wrote:1er step towards the unknown, Electric Motor Differential Analysis!

An electric coil motor can not operate fully according to the theory
.....

At the bear,

You will take courses in electrical engineering to explain your nonsense.

make an effort!

Well already a magnet does not have a power, but a force, and it probably does not measure in watts.
So if you have actually taken electrical engineering courses, there are gaps or you have to revise.

Hic wrote:I have taken courses!
Should you learn the fancais?

I repeat my question!

How is it possible that an engine can generate mechanical 1Kw on the axis,
by injecting him only 1Kw electric

So as to have a mechanical 1Kw force on the axis,
It takes 2 equal magnetic fields of 1KW magneto-mechanical EACH,
isssus an electrical power of 1KW every !!!!!!!


We note that
That's what you get on a permanent magnet motor,
1kw élecrtique + 1KW in magneto-mechanical repulsion of the magnets of the rotor = 1KW mechanical on the axis.It is OK!

and therefore a total of 2Kw magneto-mechanical in repulsion for mechanical 1KW on the axis

...

You do not understand anything about electrical engineering.

Go see you elsewhere.

And at Alsthom they make hundreds of MW engines that work quite well.
Whatever you say.

Forhorse wrote:Well already a magnet does not have a power, but a force, and it probably does not measure in watts.
So if you have actually taken electrical engineering courses, there are gaps or you have to revise.

A coil motor with no magnets, we do not care!
could you come back to the main subject ^

to get mechanical 1Kw on the axis,
since the system works in repulsion,
it will take 2 fields in opposition of the same power,

which represents 2 times the mechanical power and
therefore double the "normal" consumption

Hic wrote:...
to get mechanical 1Kw on the axis,
since the system works in repulsion,
it will take 2 fields in opposition of the same power,

which represents 2 times the mechanical power and
therefore double the "normal" consumption

Return to your pack ice and stop giving yourself false problems.

You have a problem!

Everything works very well,
but you did not understand that there is a puzzle to be solved


No kidding? did not you understand the question?

and I have nothing against "Alsthom": mrgreen: you are "kid" there

moinsdewatt wrote:

Hic wrote:I have taken courses!
Should you learn the fancais?

I repeat my question!

How is it possible that an engine can generate mechanical 1Kw on the axis,
by injecting him only 1Kw electric

So as to have a mechanical 1Kw force on the axis,
It takes 2 equal magnetic fields of 1KW magneto-mechanical EACH,
isssus an electrical power of 1KW every !!!!!!!


We note that
That's what you get on a permanent magnet motor,
1kw élecrtique + 1KW in magneto-mechanical repulsion of the magnets of the rotor = 1KW mechanical on the axis.It is OK!

and therefore a total of 2Kw magneto-mechanical in repulsion for mechanical 1KW on the axis

...

You do not understand anything about electrical engineering.

Go see you elsewhere.

And at Alsthom they make hundreds of MW engines that work quite well.
Whatever you say.