Buy and install Chinese wind turbine 2 and 3 KW
published: 02/08/07, 12:37
here I have just received this July 25 after almost 4 months waiting for delivery, two wind turbines one for me (2kw) and a second for my father (3kw).
I keep up to date a blog with photos of the follow-up of the evolution of the assembly, use and result
http://willaupuis.skyrock.com
to date they are not yet mounted, personally I am at the beginning of the assembly of the 2kw mat but must allow time to dry the concrete to support the mat
my father will probably climb the September 3kw because despite being retired he is overwhelmed with work (long live retirement)
oh yes I have some questions to the site's electricians,
at the exit of the alternator of the 2 kw (120 DC V 17A) comes out three son, I have to go to see an electrician to help me editing but here a council or two are always welcome )
1 °) on these three wires is it correct that 1 serves as a mass and the other two are they phases?
2 °) to calculate the diameter of the cable to use I will use the formula: is it correct?
S = r0 * L * I / V
r: copper resistivity = 0.021 ohms2 / m
L: total length (go + return) in m
I: Current at A and V the voltage drop.
I keep up to date a blog with photos of the follow-up of the evolution of the assembly, use and result
http://willaupuis.skyrock.com
to date they are not yet mounted, personally I am at the beginning of the assembly of the 2kw mat but must allow time to dry the concrete to support the mat
my father will probably climb the September 3kw because despite being retired he is overwhelmed with work (long live retirement)
oh yes I have some questions to the site's electricians,
at the exit of the alternator of the 2 kw (120 DC V 17A) comes out three son, I have to go to see an electrician to help me editing but here a council or two are always welcome )
1 °) on these three wires is it correct that 1 serves as a mass and the other two are they phases?
2 °) to calculate the diameter of the cable to use I will use the formula: is it correct?
S = r0 * L * I / V
r: copper resistivity = 0.021 ohms2 / m
L: total length (go + return) in m
I: Current at A and V the voltage drop.