Ban on new thermal cars in 2035: Germany changes its mind!

[Christophe]

In the imaginary world of some, yes!

A bit like, we make an almost ineffective vaccine 94% effective!

[sicetaitsimple]

and go ahead, dig...

You screwed up, it happens...I said it nicely...It's not a raw power of 60.000GW as you wrote.

[GuyGadeboisTheBack]

In the imaginary world of some, yes!

A bit like, we make an almost ineffective vaccine 94% effective!

You still haven't accepted the idea that this vaccine is indeed 94% effective for those on whom it worked...

[Remundo]

and go ahead, dig...

You screwed up, it happens...I said it nicely...It's not a raw power of 60.000GW as you wrote.

of course yes.

and per year, if you're interested, x 8766h: i.e. 525 GWh of electricity. Almost 960 PWh (PetaWatthour), or 000 TWh if you prefer.

all this for 1 km² which receives an average power of 000W solar with 000% photovoltaic efficiency.

Before saying that I'm wrong, do the math, we'll talk about it again...

[sicetaitsimple]

OK, you invented the "average annualized power" of a PV park, including nights, it is certainly a very useful notion.

[NCSH]

I have the impression that you have confused power and energy, if the map is representative of the average annualized solar power.

I have proof that you are talking nonsense.

Uh? No.
Your two cards are actually roughly consistent, between the energy received annually (about 2500kWh/year) and the average annualized power (about 300W).
300W*8760= not far from 2500kWh.
And so your 20% efficiency, you have to apply them to 2500 to get kWh, and not kW as you say.
If you apply it to 300W, you get an average annualized power, which still makes little practical sense when it comes to solar.

What matters most is the load factor of the solar fields that we consider.
This makes it possible to deduce the LCOE by calculation, ie the cost of producing electrical energy or hydrogen (LCOH).
This method of comparing the cost of intermittent energies dates from 1995.

It should be remembered that the load factor of photovoltaic panels mounted on single-axis trackers is equivalent to that of solar thermal fields with adjustable mirrors; ie DNI cards. That is a load factor almost 20% higher than simple conventional fixed photovoltaic panels.
We then arrive at these load factors of 2 H/year or even 200, or 2 and 600%.

Exceptionally, Western Australia, the Atacama Desert bursts this ceiling...

PS: it was in the LUT reports.

[sicetaitsimple]

and go ahead, dig...

You screwed up, it happens...I said it nicely...It's not a raw power of 60.000GW as you wrote.

of course yes.

and per year, if you're interested, x 8766h: i.e. 525 GWh of electricity. Almost 960 PWh (PetaWatthour), or 000 TWh if you prefer.

all this for 1 km² which receives an average power of 000W solar with 000% photovoltaic efficiency.

Before saying that I'm wrong, do the math, we'll talk about it again...

For what PV peak power installed?

[Christophe]

OK, you invented the "average annualized power" of a PV park, including nights, it is certainly a very useful notion.

An average power of 300W seems to me to include night cycles...but we're not at 94% there!

[Remundo]

OK, you invented the "average annualized power" of a PV park, including nights, it is certainly a very useful notion.

I did not invent it, it appears directly in the card that I provided to you initially.

And which was used to answer your questions about what could be extracted from 1 km² in solar energy.

I have already worked on the subject since 2008, so I know a little about what I am talking about... unlike you.

[Remundo]

For what PV peak power installed?

you just have to calculate it in kWh.