We can also compare the 1 200 000 kJ to heat the house during 7j has its equivalent in wood or oil:
Source: https://fr.wikipedia.org/wiki/Bois_%C3% ... on_du_bois
Our system saves:
1 200 000kJ / (3.9kWh / kg * 3600kJ / kW) = 85.7kg of wood
1 200 000kJ / (26GJ / t * 1 000 000kJ / GJ * 0.001kg / t) = 46.2kg of coal
1 200 000kJ / (42GJ / t * 1 000 000kJ / GJ * 0.001kg / t * 0.85kg / l) = 33.6l of FOD fuel oil
And that's all 7j in winter !! (also throughout the year but to a lesser extent)
Not too bad for a little palm oil
Store thermal energy with palm oil? Natural Phase Change Material (PCM)
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Re: Store thermal energy with palm oil?
It's about lauric acidthibr wrote:but is not more than 30% more expensive?
https://fr.wikipedia.org/wiki/Huile_de_ ... omposition
Has anyone at least experienced the trick, because we're swimming in random speculation there?
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Re: Store thermal energy with palm oil?
izentrop wrote:It's about lauric acidthibr wrote:but is not more than 30% more expensive?
https://fr.wikipedia.org/wiki/Huile_de_ ... omposition
We are abusing the language by saying palm oil, it's true, we should say "pure lauric acid" or assimilate it to coconut oil and palm kernel oil.
izentrop wrote:Has anyone at least experienced the trick, because we're swimming in random speculation there?
It is apparently good to specify that the data used are constants due to the materials used, nothing hazardous in there.
I nevertheless agree that it is necessary to test on a small scale before proceeding to the application.
I am still looking for European sites that sell lauric acid at a price below 10e / kg.
If in a week I can not find, I will buy from Chinese sites at 3e / kg.
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Re: Store thermal energy with palm oil?
I added some values
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Re: Store thermal energy with palm oil?
Mystiik wrote:So I had another idea, why encapsulate the acid in round beads and put them in water when you can put 100% acid.
The answer is that the acid will gradually crystallize around the exchanger, until completely prevent exchanges with it.
My question is: which layer of crystal is one willing to tolerate? 5mm? 10mm? 50mm?
I intuitively want to say 10mm, the system will have a little inertia due to the solid layer formed, which is appreciated for underfloor heating, moreover, the more the buffer will be "emptied" in energy, the less it will exchange with the outside, even if it remains overall at 42 ° C.
So I propose a solution based lamella:
In the case of our 7.6m3, we have a cube of 2m about.
By taking plates of metal (which does not react with lauric acid) of 2mx2mx1mm, then one can create a system in lasagna:
1 layer: lauric acid 10mm
2 layer: 1mm of resistant metal
3 layer: 2mm of water
4 layer: 1mm of resistant metal
5 layer: lauric acid 10mm
We thus have 20mm of acid for 4mm useful, so we are at 83% acid, exchanger understood, in our system.
By taking:
1 layer: lauric acid 50mm
2 layer: 1mm of resistant metal
3 layer: 2mm of water
4 layer: 1mm of resistant metal
5 layer: lauric acid 50mm
Acid 100mm is obtained for 4mm useful: 96% acid, exchanger included
For a variation of T ° from one kg of 35 to 50 ° C:
211 kJ + 2x (50-35) = 241 kJ for lauric acid
The house needs 1 200 000kJ during 7j in winter
Either divided by 241 kJ / kg buffer = 5m3 !!
We win 30% of volume
Hey Mystiik I missed your great 2019 update! Very interesting to complete this historical subject of the forum !
And so 2 years later? Did you materialize?
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