The video mounts the red orange green blue stations with colors.

A traveler wishing to go from a red station to a blue station takes the red-blue train.
In the red station, only 3 trains stop, red-green, red-orange, red-blue…

Let's take the example in station B: Trains 1, 2, 3 all pass at 10 s intervals. 10 s later, train 4 (BD) stops at the head of station B. Those who want to go to station B or D get on for 20 s 10s later, train 5 (BC) stops behind the station B. Those who want al ...

To answer "bardal", This means that, in the best case, the "gain" for 1 traveler will be the time needed for a station, no more.
The gain will be to travel 50% faster, because each train stops on average only once in 2.

To answer "sicetaitsimple": "the good, hard-working guy who starts early." He lives near station B, and he has to go to the next station "A" »He sees two trains arriving at the same time, BD at the head of the station and BC at the end of the station, so if he wants to go to B, C, D ...

a half train is a train but twice shorter, to be able to put 2 trains at the same time in the same station. There are 2 trains that stop in 6 out of 2 stations: AD, BD, CD, AC, BC, AB. Train (4) = AD => A________D__ A ________D__ A ________D__ A ________ D__… Train (1) = AC => A_____C_____ A _...

6 HALF METROS THAT STOP 2 OUT OF 4 STATIONS BUT YOU GO UP AND DOWN WHERE YOU WANT. You take the metro in any station to go to another station. Imagine that the metro only stops in one station out of two and that you advance on average 2% faster ... This is the ...