Hydrogen: pumping station at home by Honda!
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Hey there is a good table on the same link, mixing all of this and converting to the right units (this is mess) find the gray energy for H2:
Source: IFP from "Well-to-Wheels analysis of future automotive fuels and powertrains in the European context", EUCAR, JRC, CONCAWE, November 2003
Source: IFP from "Well-to-Wheels analysis of future automotive fuels and powertrains in the European context", EUCAR, JRC, CONCAWE, November 2003
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- Capt_Maloche
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Hey!
Could you correct?
There is always the same intensity in the cells in series, only the voltage is divided !! (as for batteries ) so fine 600 l / h
for 2V, ok with me it's 240V, i.e. 240/110 = 2.18V
Could you correct?
christophe wrote:If you have 20% yield yes that's it! Just something 220/110 = 2V and not 2.2. So assuming you have 100 plates for 2.2V, you would have 0.2A. (as it is in series it is the totality).
So you would have a total power of: 100 * 2.2 * 0.2 = 44W for 44 * 0.4 = 17.6W of H2 produced.
There is always the same intensity in the cells in series, only the voltage is divided !! (as for batteries ) so fine 600 l / h
for 2V, ok with me it's 240V, i.e. 240/110 = 2.18V
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Are you kidding me? You have noted well:
But whatever, 100 or 110 plates is the same for our reasoning.
In terms of intensity ... yes precisely, it is defined by the resistance across each dipole, right? So with 2.2V you will have 0.2A assuming you use the same water as the Japanese ...
Capt_Maloche wrote:I do an electrolysis in 220V rectified to 10A,
But whatever, 100 or 110 plates is the same for our reasoning.
In terms of intensity ... yes precisely, it is defined by the resistance across each dipole, right? So with 2.2V you will have 0.2A assuming you use the same water as the Japanese ...
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- Capt_Maloche
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well nois the overall resistance that prevails
if you have 10A, it is on each cell since they are in series, the same number of electrons will cross each cell to return to the generator, where then it is that they take a parallel dimension
if you have 10A, it is on each cell since they are in series, the same number of electrons will cross each cell to return to the generator, where then it is that they take a parallel dimension
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Capt_Maloche wrote:well nois the overall resistance that prevails
if you have 10A, it is on each cell since they are in series, the same number of electrons will cross each cell to return to the generator, where then it is that they take a parallel dimension
Exactly MALOCHE !! U = R * I
It is the intensity at the CELL level which defines the intensity!
A cell: 2.2 = R * 0.2
R = 11 Ohm per cell
All cells in series: R = 11 * 100
220 = 110 * 0.2
It sticks, what's wrong?
But I think that industrial electrolysers have cells mounted in // in order to have different amperes in each cell!
Anyway if you have 10A in each cell you will have a lousy return ...
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Woodcutter wrote:There is something I do not understand with these conso in MJ for 100 km, I can not find my little ...
Ben pkoi? Wait, I’m creating a specific topic!
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Found that :
http://www.bulletins-electroniques.com/ ... /55856.htm
It's not only on Econology that it phosphorus ...
http://www.bulletins-electroniques.com/ ... /55856.htm
It's not only on Econology that it phosphorus ...
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Christophe wrote:Exactly MALOCHE !! U = R * I
It is the intensity at the CELL level which defines the intensity!
A cell: 2.2 = R * 0.2
R = 11 Ohm per cell
All cells in series: R = 11 * 100
220 = 110 * 0.2
It sticks, what's wrong?
But I think that industrial electrolysers have cells mounted in // in order to have different amperes in each cell!
Anyway if you have 10A in each cell you will have a lousy yield ...
Is that so? why, then? Well re-no
What's wrong? is that you think that it passes only 1 / 110th of the current (Intensity) in each cell, which would be true if they were in parallel !!
In series, the intensity of the first cell is equal to all the others, otherwise how do you want to pass your 10A?
the result is:
P = 2200W U = 240V and I want I of the set = 10A
U = RxI and P = UxI and R total = U / I i.e. 240/10 = 24 Ohm
the resistance of each cell must be 24/110 = 0.22Ohm
and to have that, you have to "play" on the 3 mobile parameters which are the surface of the electrodes, their spacing and the acid concentration of the water
tests to come with 2 stainless steel plates 250x250mm
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Disagree ... but that's okay ...
This is where you are mistaken: it is only the spacing of the cells and the nature of the water (resistivity, salinity) that will set this value and if you get it you will probably have a return that will drop sharply ...
the resistance of each cell must be 24/110 = 0.22 Ohm
This is where you are mistaken: it is only the spacing of the cells and the nature of the water (resistivity, salinity) that will set this value and if you get it you will probably have a return that will drop sharply ...
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