Rosch Gaia yet a motor free energy
Well, I filed two applications for building permits in two different regions there are fifteen years, it was marked on the license that the construction was necessarily connected to the public electricity network (edf at the time) ... if it has changed so much, I ask myself the question of insurance coverage without passing through!
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ARMAND wrote:Well, I filed two applications for building permits in two different regions there are fifteen years, it was marked on the license that the construction was necessarily connected to the public electricity network (edf at the time) ... if it has changed so much, I ask myself the question of insurance coverage without passing through!
it turns out that I have the opposite example for my country house where the license was deposited WITHOUT EDF connection because of conflict with a neighbor who was waiting for one thing: that I pay for the 6 poles necessary for that the line arrives to our 2 homes. (conflict resolved since cost sharing and 1 year without electricity.)
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 Exnihiloest
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 posts: 5156
 Registration: 21/04/15, 17:57
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Janic wrote:here is the data provided on the patent or other close
http://patentimages.storage.googleapis. ... gb0001.png
With "immersion weight" and pressures in Kg, we can already see that we are dealing with a joker, not a scientist.
I also like the "73,4 kwh per hour"
But let's try to decode the patent. The supposed trick is to "inflate" the float at the bottom to a fixed volume. Since the volume is fixed, the pressure remains constant until the float is at the top. At the top, a set of valves allows it to communicate with the lower one opposite it. As the top float shrinks, the bottom float inflates. As the pressure is constant between the two volumes, no work would be necessary in the operation or almost nothing, a chouïa: to overcome a pressure delta of "0,4 Kg" between the top and the bottom.
So where is the error? Easy to see.
The calculation of the driving thrust is 14400 Kgs. We see in the formula that the individual thrust of a float is multiplied by the number of floats. No complaints.
The calculation of the reverse thrust, that of the lower volume floats that go down, gives 3600 Kgs. We see in the formula that the individual thrust of a float is also multiplied by the number of floats. Still nothing wrong.
The author then calculates the total work by multiplying the resulting thrust (144003600) by the height (1,10 m), and gets 11880 Kgm. It's OK.
But here is the miracle: this work of 11880 Kgm, calculated for all the floats, is now claimed to be the "work supplied by the float"!
As there are 10 active floats between the top and the bottom, the work is in the order of 1188 Kgm / float. As the air injection job is 4320 Kgm, the efficiency of the machine is at most 27,3%.
(The complete pdf of the scam or failure of high school student of his duty of physics, is there:
http://patentimages.storage.googleapis. ... 2601A1.pdf)
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Janic wrote:here is the data provided on the patent or other close
http://patentimages.storage.googleapis. ... gb0001.png
73,4 kwh per hour. Direct bin.
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The volume being fixed, the pressure remains constant until the float is at the top
Exactly you have fake and it is perhaps that lies the trick. The law of Boyle mariotte:
The volume varies according to the pressure.
http://bv.alloprof.qc.ca/chimie/lesgaz ... te%29.aspx
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 Exnihiloest
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 posts: 5156
 Registration: 21/04/15, 17:57
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raymon wrote:The volume being fixed, the pressure remains constant until the float is at the top
Exactly you have fake
No, I am right, and I prove it.
and maybe that's the trick. The law of Boyle mariotte:
The volume varies according to the pressure.
http://bv.alloprof.qc.ca/chimie/lesgaz ... te%29.aspx
The volume varies with the pressure, if the volume is not fixed (like rubber balloon, filled with air, and that is pushed into the water).
But if you push a bottle of air into the water, closed, the volume of air inside does not change, and so the pressure is not.
The float is filled with air, down to a fixed maximum volume, and that remains constant in the climb, by mechanical stress (stop). Like a submarine that moves between different depths, its airtightness and the constant volume of the cockpit maintain ipso facto the air pressure inside, fortunately for the passengers!
This is what the law of Boyle Mariotte tells us: the volume is constant in the climb, so the pressure is constant.
It is not enough to bazard any physical principle, it is necessary to understand its field of application and the conditions of its implementation.
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The float is filled with air, down to a fixed maximum volume, and remains constant in the climb
No the tank is not closed looks well the operation it is not necessary that it is because the air rises at the top of the tank. So the volume increases when approaching the surface.
This is exactly the same phenomenon as with a diving stabilizer. If you are stable at 20 m with a certain volume of air going up from 2m you will not be stable anymore and you will go up faster and faster unless you empty part of the air of the stab.
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 Exnihiloest
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 posts: 5156
 Registration: 21/04/15, 17:57
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raymon wrote:The float is filled with air, down to a fixed maximum volume, and remains constant in the climb
No the tank is not closed looks well the operation it is not necessary that it is because the air rises at the top of the tank. So the volume increases when approaching the surface.
But what are you talking about? Me it is clearly the patent that introduced Janic, I passed the link with my analysis.
Just read it.
2 page, paragraph 25:
"the gas pressure is kept constant in the deformable enclosures by introducing gas into the lower elements of the ascending portion and extracting gas from the upper elements of the descending portion. "
3 page, paragraph 25:
"The floats 3 to 3/21 have the particularity of ne ability to expand beyond the volume achieved at 3 / 2, to maintain constant internal pressure between 3 and 3 / 12."
(so between 3 / 2 down and 3 / 12 up: constant pressure and volume).
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