Revival of the controversy around the concept of Teremetz

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quartz
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Revival of the controversy around the concept of Teremetz




by quartz » 27/08/08, 13:25

Hello everybody :D

It was in 2006 I think someone talked about the principle of Teremetz,
according to which it is possible to charge a capacitor without consuming current !!
It seemed to me, like all of you, totally crazy!

here you will see a manipulation that the experimenter does not seem to understand too much himself, relative to the title.

I thought it might be worth a replication, to be honest it scratches me.

I did a lot worse, I watch this and I will keep you posted while waiting good view.

A + + +
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Cafarelli
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by Cafarelli » 22/10/08, 06:32

fun 12 + 0 = 15, it's good to be funded by any Regional Council in need of spectacular innovation

but if you had taken the Physics course in first class (electricity section), you would not fall into this coarse panel for students too close to the radiator, with a softened brain!

for my part, it dates from the 70s, certainly, my course in Physics

but I don't think the laws of Physics have changed


do some want an additional explanation, or do they prefer to remain in the dark
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by Petrus » 14/11/08, 23:22

By putting the two condos in series, we get 15V, yes, but we also halve the capacity!

so at the input we have 12V for 100µf
after the transfer we have 15 volts, but for 50µF

So no over-unity!

Association of capacitors:
http://pagesperso-orange.fr/f5zv/RADIO/ ... 23B22.html
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by Remundo » 14/11/08, 23:41

Hello Overunitists!

It is especially that it is well known that the Volt is not ... an energy : Cheesy:

Take a maxi condo at 12V

Plug it into a mini condo ... wait for balance, then unplug.

You have after 2 condos at almost 12V. The quest for double unitity? Not yet...

By neglecting the resistive losses linked to charge transfers:
Q1² / 2 / C1 + Q2² / 2 / C2 = initial energy = constant
And with the losses
Q1² / 2 / C1 + Q2² / 2 / C2 <constant

More generally, this experience obeys the following laws by neglecting losses:
* Q1ini = C1 U1ini: Q2ini = 0
* Eini = Q1ini² / 2 / C1
* Q1fin / C1 = Q2fin / C2
* Q1fin²/2/C1+Q2fin²/2/C2=Eini
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by Cafarelli » 15/11/08, 07:41

view the video

the yield is less than 1, elementary calculation done, in all cases

the laws of Physics are respected


PS: do not confuse energy, power and electrical voltage ...

if I was a teacher (God forbid), 0/20 pointed
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