Good evening Patatrace!
Here in Canada we use the same wire and the same boxes as for a conventional power supply 120 volts so it is better to use the same wire and boxes as for 220-230 volts from your home, more if the standard LEDs becomes in 220-230 volts, you'll be ready!
So you will have no problem with insurers in case of fire!
12V DC power supply - 2 maximum cable meters?
In fact if I put everything in 12v is because it is about to equip a piece of 18 spots with a single arrival of current. But if I remember correctly in the RGIE we can not put more 8 bright spots with a single source 220v, right?
This is a renovation, that's why there is only one lamp circuit.
The length of the cables is explained by the fact that the transformer will be located in the next room to not see it (finally the lid that comes out of the false ceiling).
I also think that by grouping everything on a single transformer there should be fewer losses due to the current conversion on each individual GU10 transformer.
Thank you for your valuable advice, I will install everything in 2,5mm² (except the 20cm son of high temperature spot which remain in 1,5mm²).
Out of curiosity, can anyone tell me what I should get as voltage drop after 10m of 2,5mm² cable? I will give the right answer when I have everything connected
This is a renovation, that's why there is only one lamp circuit.
The length of the cables is explained by the fact that the transformer will be located in the next room to not see it (finally the lid that comes out of the false ceiling).
I also think that by grouping everything on a single transformer there should be fewer losses due to the current conversion on each individual GU10 transformer.
Thank you for your valuable advice, I will install everything in 2,5mm² (except the 20cm son of high temperature spot which remain in 1,5mm²).
Out of curiosity, can anyone tell me what I should get as voltage drop after 10m of 2,5mm² cable? I will give the right answer when I have everything connected
0 x
Taking the resistivity of the copper (17 * 10 ^ (- 9) Ohm.meter), the resistance of the main line of 10 m in 2,5 mm² makes 0.068 Ohm
the voltage drop depends on the amperage: for 10A (120W in 12V), you lose R x I = 0.68V, ie 5.6% of the voltage at the top of the line
and you dissipate R x I² = 6.8 W, ie 5.6% of the power injected on the line.
the voltage drop depends on the amperage: for 10A (120W in 12V), you lose R x I = 0.68V, ie 5.6% of the voltage at the top of the line
and you dissipate R x I² = 6.8 W, ie 5.6% of the power injected on the line.
0 x
Hello Forhorse,
undeniable, but ... I still feel that you cut electrons 4.
It will be necessary to make the calculations to the nearest μV as soon as Patatrace has given its plans.
One could also take into account the uncertainties about the length of the cables, and the local variations of copper section, the inhomogeneities resistivity of the material.
undeniable, but ... I still feel that you cut electrons 4.
It will be necessary to make the calculations to the nearest μV as soon as Patatrace has given its plans.
One could also take into account the uncertainties about the length of the cables, and the local variations of copper section, the inhomogeneities resistivity of the material.
0 x
That's what it gives in a very schematic way:
I put numbers in brackets in order to be able to give an individual value by calculation. The derivation is done in the blue boxes which are connected to each other then to the big junction box with the 100W transformer. Between hook I have each time calculated the total length per wire (to be doubled so if necessary).
As a reminder, the power supply has two outputs which allows to distribute the load. It also has a potentiometer in case it should give a boost, but I hope I do not have to touch it. I do not have an ammeter clamp so I can give the final only the voltage and consumption measured at the socket via a good wattmeter (margin + -0,5W).
The length of each wire is calculated with a possible variation of + -5cm.
I put numbers in brackets in order to be able to give an individual value by calculation. The derivation is done in the blue boxes which are connected to each other then to the big junction box with the 100W transformer. Between hook I have each time calculated the total length per wire (to be doubled so if necessary).
As a reminder, the power supply has two outputs which allows to distribute the load. It also has a potentiometer in case it should give a boost, but I hope I do not have to touch it. I do not have an ammeter clamp so I can give the final only the voltage and consumption measured at the socket via a good wattmeter (margin + -0,5W).
The length of each wire is calculated with a possible variation of + -5cm.
0 x
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