Garage door motor consumption

[Asget]

Hi I am looking for the consumption of garage doors, for a cycle (1 opening and full closing).
The engine in question is a SupraMatic P of the Hormann brand.
Links: http://www.gamalin.com/hormann-supramatic.htm

I know the power of the motor is 500W and that's about it.

Also I don't know how to take it, without making a measurement by consometer to evaluate this consumption.


So if you have an idea I'm interested.

[Gaston]

By timing the opening and closing times, we can have, if not an exact value, at least an upper bound.

For example, if the full cycle runs the engine for one minute, the consumption is less than 500 * 1/60 = 8,3 Wh per cycle.

Actual consumption will depend on the weight of the door, friction, wind speed ... and can only be measured.

[Asget]

Yes I think that I will leave on this method being given that I do not have other information.

Thank you for the answer.

[Gaston]

If it's not intrusive, why ask the question

The consumption of this kind of device is anyway very low (unless you enter a parking lot in a very large building, but in this case, the equipment you offer is not suitable)

[dedeleco]

There are power measurement devices which also give consumption in KWh over the chosen time !!

Otherwise, simply if the power is 500W over one minute to open, the consumption is 0,5KWx1 / 60h = 8,3millieth of KWh or 8,3 ten thousandths of € at random to 50% !!

Unless you open and close every minute, consumption is not high !!

[Asget]

If I take 1 min for closing and 1 min for opening
Its 500 * 2/60 = 16.6 Wh per cycle

If I use my garage regularly for example 6 cycles per day (family with 2 cars)

(16.6 * 6 * 365) / 1000 = 36.354 kWh / year

Or less than an answering phone (45 kWh / year)
Source: (ADEME) http://www.enertech.fr/pdf/9/consommati ... nagers.pdf

It seems correct as an estimate

[Gaston]

(16.6 * 6 * 365) / 1000 = 36.354 kWh / year

Or less than 5 euros per year of consumption.
You were really scared for your budget

It seems correct as an estimate

It is even overestimated, because the engine does not provide its maximum power during the entire maneuver (and 1 minute to open the door, it's very looong, especially when waiting outside).

To be precise, it would also be necessary to know the consumption of the radio receiver in standby


I have never seen anyone ask for the annual consumption of the house bell for 10 bells per day