Yes, but that's a bit lame as a remark, you can also theoretically leave the orbit of a planet with an ionic engine!Gildas wrote:A priori it does not matter the mass of the object to be sent:The rate of release is a scalar, not a vector quantity: it just specifies an amplitude, not a direction. An object which moves at the speed of release can escape the gravitational field whatever its initial direction (insofar as the trajectory does not meet the surface of the star). It does not depend either on the mass of the object, only on that of the star.
https://fr.wikipedia.org/wiki/Vitesse_d ... 9ristiques
And why didn't you say then that you wanted to trap us by knowing the answer to the question you are asking (and not to try to understand?) And that you bounce back each time by finding loopholes in the answers that are data and which are not “false”, while preserving suspense.
I was just saying that AS LONG AS YOU DON'T GIVE THE MASS of what to get out of Earth's orbit, it is not possible to calculate this: DO YOU DEMAND that you have to deduct the 9.81 m / s necessary (or whatever the number) to escape the earth's gravity of the total thrust necessary to get a machine of a given mass out of the gravity field? That's what this phrase from wikipedia IMHO means.
If I throw you a sheet of paper folded in the shape of an airplane wing, I make it fly, for a moment my “plane” escapes the earth's attraction. But I don't think I can do the same by throwing a Soyuz ship “by hand”.